SOLUTION: two planes are 1380mi apart and traveling towards each other. one plane is traveling 80mph faster than the other plane. the planes pass each other in 1.5hours.find the speed of eac
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Question 971280: two planes are 1380mi apart and traveling towards each other. one plane is traveling 80mph faster than the other plane. the planes pass each other in 1.5hours.find the speed of each plane Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! two planes are 1380mi apart and traveling towards each other. one plane is traveling 80mph faster than the other plane. the planes pass each other in 1.5hours.find the speed of each plane
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slower plane speed:: x mph
faster plane speed:: x+80 mph
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Closing speed of the two planes:: 2x+80 mph
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Equation to solve for "x"::
1.5(2x+80) = 1380
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1.5*2x + 1.5*80 = 1380
3x = 1260
x = 420 mph (slower plane speed)
x+80 = 500 mph (faster plane speed)
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Cheers,
Stan H.
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