SOLUTION: A person leaves home at 7:00 a.m. and drives to a destination at a rate of forty mph. After spending one hour at the destination, the person returns at a rate of twenty-five mph an

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: A person leaves home at 7:00 a.m. and drives to a destination at a rate of forty mph. After spending one hour at the destination, the person returns at a rate of twenty-five mph an      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 971276: A person leaves home at 7:00 a.m. and drives to a destination at a rate of forty mph. After spending one hour at the destination, the person returns at a rate of twenty-five mph and arrives home at 2:30 p.m. How far is the trip to the destination?
Found 2 solutions by JoelSchwartz, Alan3354:
Answer by JoelSchwartz(130) About Me  (Show Source):
You can put this solution on YOUR website!
t=the time it took to get to the destination traveling forty miles per hour.
x=amount of time it took to return home from the destination traveling twenty five miles per hour.
t+1+x=7.5
t+x=6.5
d=number of miles each way
40t=d
25x=d
25x=40t
t=6.5-x
25x=40(6.5-x)
25x=260-40x
65x=260
x=4
d=25*4
The trip is 100 miles to the destination. To go back to where the person started from it would take 200 miles of traveling.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A person leaves home at 7:00 a.m. and drives to a destination at a rate of forty mph. After spending one hour at the destination, the person returns at a rate of twenty-five mph and arrives home at 2:30 p.m. How far is the trip to the destination?
---------------
Avg RT speed = 2*40*25/(40+25) = 400/13 mi/hr
6.5 hours driving
d = r*t = (400/13)*(13/2) = 200 miles RT
100 miles each way