SOLUTION: Please help me am struggling with logarithms: 1log5^x=log5^(x-1)

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Question 971197: Please help me am struggling with logarithms: 1log5^x=log5^(x-1)
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
The expression within each log function would be equal:

1%2Alog%28%285%5Ex%29%29=log%28%285%5E%28x-1%29%29%29

5%5Ex=5%5E%28x-1%29
and here, the exponents would be equal because each member uses the same base.

x=x-1
and that is impossible.
NO SOLUTION