SOLUTION: Metal A contains 81% tin and 5% copper.
Metal B contains 1% tin and 20% copper.
What is the ratio metals A and B need to be combined in to get a mixture that is 3:1 tin to copper
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-> SOLUTION: Metal A contains 81% tin and 5% copper.
Metal B contains 1% tin and 20% copper.
What is the ratio metals A and B need to be combined in to get a mixture that is 3:1 tin to copper
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Question 971132: Metal A contains 81% tin and 5% copper.
Metal B contains 1% tin and 20% copper.
What is the ratio metals A and B need to be combined in to get a mixture that is 3:1 tin to copper? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Metal A contains 81% tin and 5% copper.
Metal B contains 1% tin and 20% copper.
What is the ratio metals A and B need to be combined in to get a mixture that is 3:1 tin to copper?
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Amt of tin:: 0.81A+ 0.01B
Amt of CU::: 0.05A+ 0.20B
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Equation:
[0.81A+0.01B]/[0.05A+0.20B] = 3/1
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0.81A + 0.01B = 0.15A+0.60B
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0.66A = 0.59B
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Ans: A: B = 0.59:0.66
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Cheers,
Stan H.
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