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x^2 -5x -6 <=0
factorising the left hand side of the expression
(x-6)(x+1) <=0
the product of 2 numbers will be <=0 when one is >=0 and the other <=0
case 1
x-6 <=0 and x+1 >=0
gives x<=6 and x>= -1
Solution set is [-1,6]
ie -1<=x<=6
case 2
x-6 >=0 and x+1 <=0
gives
x>=6 and x<= -1
which does not hold true for any x
hence the only solution is [-1,6]
ie -1<=x<=6
