SOLUTION: At 9:00 in the mornong, two bicyclists heading opposite directions pass each other on a bicycle path. THe bicyclist headong north is going 4km/h faster than the other guy. AT 10:30
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Question 971001: At 9:00 in the mornong, two bicyclists heading opposite directions pass each other on a bicycle path. THe bicyclist headong north is going 4km/h faster than the other guy. AT 10:30, they ate 39km apart. Whats the rate of the two bicylists? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! slower cyclist is x kph
faster cyclist is x+4 kph
in 1.5 hours, their distance is 39 km
39 km/1.5 hours is 26 kph
x+ (x+4) =26
2x +4=26
2x=22
x=11
x=4=15
They are traveling apart at 26 kph; in 1.5 hours they will be 39 km apart.
The slower is traveling at 11kph; the faster at 15 kph.
