You can put this solution on YOUR website! Find the probability of obtaining at least one 6 when
(1) 5 dice are thrown,
Ans: P(1<=x<=5) = 1 - P(x = 0) = 1-(5/6)^5 = 0.598
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(2) n dice are thrown.
Ans: P(1<=x<=n) = 1 - P(x=0) = 1 - (5/6)^n
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Cheers,
Stan H.
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