SOLUTION: If you can fit 105 3in cubes in a box that measures 21in by 9in by 15 in, How much wrapping paper would you need to wrap the rectangular prism with the cubes inside?

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Question 970663: If you can fit 105 3in cubes in a box that measures 21in by 9in by 15 in, How much wrapping paper would you need to wrap the rectangular prism with the cubes inside?
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
The width of the wrapping paper is needed as part of solving the question. The box to be wrapped is described, and the "If..." part is not important.

21*9*15 volume using those dimensions will have a surface area: 2%2821%2A9%2B9%2A15%2B15%2A21%29 square inches. This is 1278 square inches surface area of the box.

The length to use of the wrapping paper depends on the width of the wrapping paper. At least 1278%2A+in%5E2 of paper will be needed. Certainly MORE, because of the need to overlap and fasten with adhesive tape.