SOLUTION: Michael has 3 quarters, 2 dimes, and 3 nickels in his pocket. He randomly draws two coins from his pocket, one at a time, and they are both dimes. He says the probability of that o
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Question 970653: Michael has 3 quarters, 2 dimes, and 3 nickels in his pocket. He randomly draws two coins from his pocket, one at a time, and they are both dimes. He says the probability of that occurring is 1
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because 2 of the 8 coins are dimes. Is he correct? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! No.
Probability of the first coin being a dime is 1/8.
The probability of the second coin being a dime, given that 1 dime is gone, is 1/7, because 7 coins remain.
The joint probability is (1/56).
