SOLUTION: Travis made a business trip of 198 miles. He averaged 52 mph for the first part of the trip and 60 mph for the second part. If the trip took 3.5 hours , how long did he travel at

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Travis made a business trip of 198 miles. He averaged 52 mph for the first part of the trip and 60 mph for the second part. If the trip took 3.5 hours , how long did he travel at      Log On

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Question 970647:
Travis made a business trip of 198 miles. He averaged 52 mph for the first part of the trip and 60 mph for the second part. If the trip took 3.5 hours , how long did he travel at each rate?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
D=RT
198=(52X)+(60*(3.5-X))
198=52X+210-60X
210-198=60X-52X
12=8X
X=12/8
X=1.5 HOURS F0R THE 52 MPH TRIP.
3.5-1.5=2 HOURS FOR THE 60 MPH TRIP.
PROOF:
198=52*1.5+60*2
198=78+120
198=198