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F=number of 50 paisa coins; T=number of 25 paisa coins
F+T=11
F=11-T Use this below to substitute for F.
rs 0.50F+ rs 0.25T=rs 5.00 Substitute for F from above
rs 0.50(11-T)+0.25T=rs 5.00
rs 5.50-0.50T+0.25T=rs 5.00 Subtract rs 5.50 from each side.
-rs 0.25T= rs -0.50 Divide each side by (-rs 0.25)
T=t ANSWER 1: There are two 25 paisa coins.
F=11-T=11-2=9 ANSWER 2: There are nine 50 paisa coins
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CHECK:
rs 0.50F+ rs 0.25T=rs 5.00
rs 0.50(9)+rs 0.25(2)=RS 5.00
rs 4.50+rs 0.50=rs 5.00
rs 5.00=rs 5.00
