SOLUTION: Given h(x)=2x to the power of 3 minus 5x to the power of 2 minus 4x plus 3. Find the intercepts of h(x)

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Question 970518: Given h(x)=2x to the power of 3 minus 5x to the power of 2 minus 4x plus 3. Find the intercepts of h(x)
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
Given
h%28x%29=2x%5E3-+5x%5E2+-4x+%2B+3
Find the intercepts of h%28x%29, or find the zeros
2x%5E3-+5x%5E2+-4x+%2B+3=0
2x%5E3-+6x%5E2%2Bx%5E2+-3x+-x%2B+3=0
%282x%5E3-+6x%5E2%29%2B%28x%5E2+-3x%29+-%28x-+3%29=0
2x%5E2%28x-+3%29%2Bx%28x+-3%29+-%28x-+3%29=0
%282x%5E2%2Bx-1%29%28x-3%29=0
%282x%5E2%2B2x-x-1%29%28x-3%29=0
%28%282x%5E2%2B2x%29-%28x%2B1%29%29%28x-3%29=0
%282x%28x%2B1%29-%28x%2B1%29%29%28x-3%29=0
%282x-1%29+%28x%2B1%29+%28x-3%29=0
solutions:
if %282x-1%29+=0=>2x=1=>x=1%2F2
if +%28x%2B1%29=0=>x=-1
if %28x-3%29=0=>x=3
so, the intercepts are at:
(1%2F2,0)
(-1,0)
(3,0)