SOLUTION: Find the value of tan2x on the interval (pi/2,pi) given that sin=(1/2)

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Question 970380: Find the value of tan2x on the interval (pi/2,pi) given that sin=(1/2)
Answer by lwsshak3(11628) About Me  (Show Source):
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Find the value of tan2x on the interval (pi/2,pi) given that sin=(1/2)
sinx=1/2 (Q2)
cosx=-√3/2
sin2x=2sinxcosx=2*1/2*-√3/2=-√3/2
cos2x=cos^(x)-sin^2(x)=3/4-1/4=1/2
tan2x=sin2x/cos2x=-√3