SOLUTION: use of graphical method to solve max z=2x+3y subject to the constraints x+y<=30 y>=3 0<=y<=12 x-y>=0 0<=x<=20

Algebra ->  Graphs -> SOLUTION: use of graphical method to solve max z=2x+3y subject to the constraints x+y<=30 y>=3 0<=y<=12 x-y>=0 0<=x<=20      Log On


   



Question 970263: use of graphical method to solve
max z=2x+3y
subject to the constraints
x+y<=30
y>=3
0<=y<=12
x-y>=0
0<=x<=20

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Map out the feasible region and find the possible vertices.
.
.
.

.
.
.
(3,3):z=2%283%29%2B3%283%29=6%2B9=15
(12,12):z=2%2812%29%2B3%2812%29=24%2B36=60
(18,12):z=2%2818%29%2B3%2812%29=36%2B36=highlight%2872%29
(20,10):z=2%2820%29%2B3%2810%29=40%2B30=70
(20,3):z=2%2820%29%2B3%283%29=40%2B9=49