SOLUTION: A rectangle has length 40 inches and width 10.2 inches. Find the length in inches of another rectangle of equal area whose width is 8 inches.

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Question 970242: A rectangle has length 40 inches and width 10.2 inches. Find the length in inches of another rectangle of equal area whose width is 8 inches.
Answer by LinnW(1048) About Me  (Show Source):
You can put this solution on YOUR website!
The area of the first rectangle is 40*10.2 = 408
Set L = the length of the rectangle with with 8
8*L = 408
divide each side by 8
L = 51