SOLUTION: The prom brought in $6300 last year.
This year, they lowered the price by 3 dollars, and ended up selling 48 more tickets. They earned $5970. What was the original price per ticke
Question 970226: The prom brought in $6300 last year.
This year, they lowered the price by 3 dollars, and ended up selling 48 more tickets. They earned $5970. What was the original price per ticket (last year), and how many tickets were sold at the lower price (this year) Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
P=original price (last year); N=number of tickets (last year)
PN=$6300
N=$6300/P
. Substitute for N.
.
.
. Subtract $6156 from each side.
. Convert to common denominator.
. Multiply by P.
. Add $186P to each side.
.
Quadratic equation (in our case ) has the following solutons:
For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=3663396 is greater than zero. That means that there are two solutions: .
Quadratic expression can be factored:
Again, the answer is: 18, -21.875.
Here's your graph:
.
The price of a prom ticket last year was $18, so:
$6300/$18=350 There were 350 tickets sold last year.
.
The price of the prom this year was $15 ($18-$3=$15)
$5970/$15=398 There were 398 tickets sold this year.(48 more than last year)