Question 970218: Find the values for x and y using the given slope.
m= 5/3 and (3,7), (x,2), (-3,y)
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! slope using first two points, (3,7) and (x,2) is (-5)/x-3 ; we subtract the 7 from the 2 (difference in y) and 3 from x (difference in x). Notice we have an x generic for slope and an algebraic x.
slope using the first and third points will be equal to the first if we have a line. That slope is (y-7)/(-3-3) or (y-7)/-6
Set them equal to 5/3 since that is the numerical value of the slope given.
[-5/(x-3)]=5/3
Cross multiply. -15=5(x-3)
-15=5x-15 by distributing.
add 15 to both sides.
0=5x; x=0
[(y-7)/-6]=5/3
Cross multiply
3(y-7)=(-6)*5)
3y-21=-30
3y=-9, adding 21 to both sides
y=-3, dividing both sides by 3
(3,7)
(0,2)
(-3, -3) are the points.
Check slope between the points
(3,7) and (0,2); (2-7))/(0-3) ; -5/-3 or 5/3
(0,2) and (-3,-3); (-3-2)/-3 ; -5/-5 or 5/3
x=0
y=-3
Notice that the points are on the line y=(5/3)x +2
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