SOLUTION: find three consecutive even integers such that three times the first integer is eight more than the sum of the second and third integers

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Question 970197: find three consecutive even integers such that three times the first integer is eight more than the sum of the second and third integers
Answer by lwsshak3(11628) About Me  (Show Source):
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find three consecutive even integers such that three times the first integer is eight more than the sum of the second and third integers
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let x=1st consecutive even integer
x+2=2nd consecutive even integer
x+4=3rd consecutive even integer
..
3x=x+2+x+4+8
x=14
x+2=16
x+4=18
1st consecutive even integer=14
2nd consecutive even integer=16
3rd consecutive even integer=18