SOLUTION: The length of a rectangle is sixteen more than four times the width. what is the area of the rectangle as a polynomial? What are the dimensions of a different rectangle with an equ

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The length of a rectangle is sixteen more than four times the width. what is the area of the rectangle as a polynomial? What are the dimensions of a different rectangle with an equ      Log On


   



Question 970152: The length of a rectangle is sixteen more than four times the width. what is the area of the rectangle as a polynomial? What are the dimensions of a different rectangle with an equivalent area?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x= width
length is (4x+16)
Area is x*(4x+16)=4x^2 +16x
That would be a rectangle of width 5 and length 36
Area is 180.


Equivalent polynomial with area 180
length would be 20 and width 9.
A rectangle has length 7 less than three times the width.
width=y
length=3y-7
area= 3y^2-7y
A polynomial with equivalent area would be a rectangle with the width twice the previous example and the length 8 more than the width.
Then the width would be 2x and the length (2x+8). Area is 2x*(2x+8)= 4x^2 +16x.