SOLUTION: Line AOB is a straight line, angle AOC=5x, angle COD=(3x+30), and angle DOB=(2x+10). Find the value of x.

Algebra ->  Angles -> SOLUTION: Line AOB is a straight line, angle AOC=5x, angle COD=(3x+30), and angle DOB=(2x+10). Find the value of x.      Log On


   

Question 97003: Line AOB is a straight line, angle AOC=5x, angle COD=(3x+30), and angle DOB=(2x+10). Find the value of x.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Here's a drawing to see what's going on:

note: this drawing is not to scale


Here we can see that all of the angles are formed from intersecting lines that meet with AOB. Also, we can see that these angles all add up to 180 degrees (since they are all supplementary)


So that means that the sum of all of the angles is 180

So it can be translated to....

5x%2B%283x%2B30%29%2B%282x%2B10%29=180



5x%2B3x%2B30%2B2x%2B10=180 Remove the parenthesis


10x%2B40=180 Combine like terms on the left side


10x=180-40Subtract 40 from both sides


10x=140 Combine like terms on the right side


x=%28140%29%2F%2810%29 Divide both sides by 10 to isolate x



x=14 Divide

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Answer:
So our answer is x=14