SOLUTION: What is the sixth term of the geometric sequence whose third term is 16 and eighth term is 512/243?

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Question 969853: What is the sixth term of the geometric sequence whose third term is 16 and eighth term is 512/243?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
What is the sixth term of the geometric sequence whose third term is 16 and eighth term is 512/243?
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a*r^2 = 16
a*r^7 = (512/243)
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Divide bottom by top to solve for "r":
r^5 = (2^9/3^5)/(2^4) = (2^5/3^5)
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r = 2/3
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Ans: a*r^5 = 2^4(2/3)^5
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Cheers,
Stan H.
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