SOLUTION: I am trying to solve and graph x^2+y^2+4x+2y-20=0.
I came up with (-2,-1) radius 5 but I think something is wrong
Algebra ->
Graphs
-> SOLUTION: I am trying to solve and graph x^2+y^2+4x+2y-20=0.
I came up with (-2,-1) radius 5 but I think something is wrong
Log On
Question 96952: I am trying to solve and graph x^2+y^2+4x+2y-20=0.
I came up with (-2,-1) radius 5 but I think something is wrong Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! x^2+y^2+4x+2y-20=0.
Complete the square separately on the x-terms and the y-terms:
x^2+4x+? + y^2+2y+# = 20+?+#
x^2+4x+4 + y^2+2y+1 = 20+4+1
Factor:
(x+2)^2 + (y+1)^2 = 25
Circle with center at (-2,-1)
Radius = sqrt25 = 5
============
Cheers,
Stan H.
(