SOLUTION: {{{ g(x) = log_3((x+6)/2) }}} i. find the domain of g in interval form ii. find the x-intercept(s) of the graph of g In what quadrant does the terminal side of an angle of

Algebra ->  Trigonometry-basics -> SOLUTION: {{{ g(x) = log_3((x+6)/2) }}} i. find the domain of g in interval form ii. find the x-intercept(s) of the graph of g In what quadrant does the terminal side of an angle of       Log On


   

Question 969216: +g%28x%29+=+log_3%28%28x%2B6%29%2F2%29++
i. find the domain of g in interval form
ii. find the x-intercept(s) of the graph of g

In what quadrant does the terminal side of an angle of 5 radians lie? justify your answer
Find all solutions for the equation: +sqrt%283%29sec%284t%29+=+-2+
Thank you
Found 2 solutions by solver91311, lwsshak3:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


The beginning of Quadrant IV is which is a little over 4 and a half. The end of Quadrant IV is which is a little over 6 and a quarter.



John

My calculator said it, I believe it, that settles it

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
+g%28x%29+=+log_3%28%28x%2B6%29%2F2%29++
i. find the domain of g in interval form
x+6≥0
x≥-6
(-6, ∞)
..
ii. find the x-intercept(s) of the graph of g
set g=0
log_3((x+6)/2)=0
exponential form: base(3) raised to log of number(0)=number((x+6)/2)
3^0=(x+6)/2
1=(x+6)/2
x+6=2
x=-4
..
In what quadrant does the terminal side of an angle of 5 radians lie? justify your answer
use degrees:
5 radians/π*180≈286˚
5 radians lie in quadrant IV
..
Find all solutions for the equation:
+sqrt%283%29sec%284t%29+=+-2+
sec(4t)=-2/√3
cos(4t)=-√3/2
4t=5π/6+2πk, 7π/6+2πk, k=any integer
t=5π/24+2πk, 7π/24+2πk, k=any integer