SOLUTION: An integer is three more than another integer. Twice the larger integer is two less than the square of the smaller integer. Find the two integers

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Question 969156: An integer is three more than another integer. Twice the larger integer is two less than the square of the smaller integer. Find the two integers
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
larger integer = x
smaller integer = y

x = y + 3
2x = y^2 - 2

Use substitution.

2(y + 3) = y^2 - 2
2y + 6 = y^2 - 2
0 = y^2 - 2y - 8
0 = (y - 4)(y + 2)

The integers are (x, y) = (7, 3) or (1, -2).