Question 969125: Suppose Tom has 19 coins totaling $3.40. If he has only dimes and quarters, how many of each type does he have ? Found 2 solutions by Alan3354, stanbon:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Suppose Tom has 19 coins totaling $3.40. If he has only dimes and quarters, how many of each type does he have ?
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D + Q = 19 (# of coins)
10D + 25Q = 340 (value of coins)
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You can put this solution on YOUR website! Suppose Tom has 19 coins totaling $3.40. If he has only dimes and quarters, how many of each type does he have ?
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d + q = 19 coins
10d + 25q = 340 cents
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Modify for elimination::
2d + 2q = 2*19
2d + 5q = 68
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Subtract and solve for "q":
3q = 30
q = 10 (# of quarters)
d = 19-10 = 9 (# of dimes)
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Cheers,
Stan H.
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