SOLUTION: How do you solve ln(x+1)-lnx=2

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Question 968829: How do you solve ln(x+1)-lnx=2
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+ln%28+x%2B1+%29++-+ln%28+x+%29++=+2+
+ln%28+x%2B1+%29++-+ln%28+x+%29++=+ln%28+e%5E2+%29+
+ln%28+%28+x%2B1+%29+%2F+x+%29+=+ln%28+e%5E2+%29+
+%28+x%2B1+%29+%2F+x+=+e%5E2+
+x+%2B+1+=+e%5E2%2Ax+
+e%5E2%2Ax+-+x+=+1+
+x%2A%28+e%5E2+-+1+%29+=+1+
+x+=+1+%2F+%28+e%5E2+-+1+%29+
-----------------------
check answer with calculator:
+e%5E2+=+7.389056+
+e%5E2+-+1+=+6.389056+
+1+%2F+%28+e%5E2+-+1+%29+=+.156518+
----------------------------
+ln%28+.156518+%2B+1+%29++-+ln%28+.156518+%29++=+2+
+ln%28+1.156518+%29+-+ln%28+.156518+%29+=+2+
+.145414+-+%28+-1.854584+%29+=+2+
+1.999998+=+2+
OK -error due to rounding off