Question 96877: A navigator at point A observes the measure of the angle of elevation to the top of the cliff to be 15 degress. This measure changes to 26 degress at B. If the height of the cliff is known to be 750m, how far has the boat moved to get from point A to point B?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A navigator at point A observes the measure of the angle of elevation to the top of the cliff to be 15 degress.
This measure changes to 26 degress at B.
If the height of the cliff is known to be 750m, how far has the boat moved to get from point A to point B?
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Let the distance from A to the base of the cliff be "x".
tan(15) = 750/x
x=750/tan(15) = 2799.038...m
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Similarly, let the distance from B to the base of the cliff be "y"
y = 750/tan(26) = 1537.728.. m
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Therefore distance from A to B is x-y = 1261.31 m
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Cheers,
Stan H.
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