SOLUTION: In desperate need of help with this one, A sound wave has frequency 50 Hz (i.e. it has wavelength (period) = 0.02 seconds). Within each beat, the highest sound intensity is 100 de

Algebra ->  Trigonometry-basics -> SOLUTION: In desperate need of help with this one, A sound wave has frequency 50 Hz (i.e. it has wavelength (period) = 0.02 seconds). Within each beat, the highest sound intensity is 100 de      Log On


   



Question 968750: In desperate need of help with this one,
A sound wave has frequency 50 Hz (i.e. it has wavelength (period) = 0.02 seconds). Within each beat, the highest sound intensity is 100 decibel (dB) and the lowest intensity is 60 dB. Supposing that t = 0 corresponds to the low intensity, write down a trigonometric function that describes this sound wave. Sketch the sound wave over two periods.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A sound wave has frequency 50 Hz (i.e. it has wavelength (period) = 0.02 seconds). Within each beat, the highest sound intensity is 100 decibel (dB) and the lowest intensity is 60 dB. Supposing that t = 0 corresponds to the low intensity, write down a trigonometric function that describes this sound wave. Sketch the sound wave over two periods.
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Wavelength is distance, not time.
Period = 0.02 seconds
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S(t) = 20*sin(x*2pi/0.02) + 80
Add the phase shift
= 20%2Asin%28x%2A%282pi%2F.02+%29+-+%28pi%2F4%29%2F0.02%29+%2B+80
= 20%2Asin%28x%2A%28100pi%29+-+%28pi%2F4%29%2F0.02%29+%2B+80
= 20%2Asin%28x%2A%28100pi%29+-+%2812.5pi%29%29+%2B+80