SOLUTION: What is a positive integer squared plus 9 times its consecutive integer is equal to 19?

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Question 968569: What is a positive integer squared plus 9 times its consecutive integer is equal to 19?
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + 9(x+1) = 19
x^2 + 9x + 9 = 19
x^2 + 9x - 10 = 0
(x + 10)(x - 1) = 0

x is positive, so x = 1.