Question 968366: Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).
The test statistic in a left-tailed test is z = -2.05
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).
The test statistic in a left-tailed test is z = -2.05
------
p-value = p(z < -2.05) = normalcdf(-100,-2.05) = 0.0218
----
Since the p-value is less than 5%, reject Ho.
-----------
Cheers,
Stan H.
-------------
|
|
|
