SOLUTION: 4x^2+2y^2+32x+4y+2=0 Find the equation of the ellipse in standard form

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Question 968242: 4x^2+2y^2+32x+4y+2=0
Find the equation of the ellipse in standard form

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
4x%5E2%2B2y%5E2%2B32x%2B4y%2B2=0

Put the x terms together and the y terms together and subtract the constant
term from both sides:

4x%5E2%2B32x%2B2y%5E2%2B4y=-2

Factor the 4 out of the first three terms and factor 2 out of the last
three terms on the left, skipping a space at the end of each parentheses:



Complete the square in the first parentheses:
To the side or in your head,
1. Multiply the coefficient of x, which is 8, by 1/2, getting 4
2. Square 4, getting 16.
3. Add inside the first parentheses
4. Add 4 times 16 or +64 to the right side, since the first parentheses
   is multiplied by 4.



Complete the square in the second parentheses:
To the side or in your head,
1. Multiply the coefficient of y, which is 2, by 1/2, getting 1
2. Square 1, getting 1.
3. Add 1 inside the second parentheses
4. Add 2 times 1 or +2 to the right side, since the second parentheses
   is multiplied by 2.

4%28x%5E2%2B8x%2B16%29%2B2%28y%5E2%2B2y%2B1%29=-2%2B64%2B2

Factor the trinomials inside the parentheses, combine the numbers on
the right:

4%28x%2B4%29%28x%2B4%29%2B2%28y%2B1%29%28y%2B1%29=64

Write the two equal factors as squares of binomials:

4%28x%2B4%29%5E2%2B2%28y%2B1%29%5E2=64

Get 1 on the right side by dividing every term by 64

4%28x%2B4%29%5E2%2F64%2B2%28y%2B1%29%5E2%2F64=64%2F64

Divide each numerator and denominator on the left by the coefficient
of the squared binomial in the numerator:

%28x%2B4%29%5E2%2F16%2B%28y%2B1%29%5E2%2F32=1

Edwin