SOLUTION: If $80,000 is invested part at 8% and the rest at 10%, and the interest from one year is $7,800, how much was invested at 10%?

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: If $80,000 is invested part at 8% and the rest at 10%, and the interest from one year is $7,800, how much was invested at 10%?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 968188: If $80,000 is invested part at 8% and the rest at 10%, and the interest from one year is $7,800, how much was invested at 10%?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If $80,000 is invested part at 8% and the rest at 10%, and the interest from one year is $7,800, how much was invested at 10%?
-------------
Equation:
int + int = interest
----
0.10x + 0.08(80,000-x) = 7800
-----------
10x + 8*80000 - 8x = 780000
2x = 780000-640000
2x = 120000
x = $60,000 (amt. invested at 10%)
------------
Cheers,
Stan H.
-----------------