a) 1/(1*2^2) + 1/(2*3^2) + 1/(3*4^2)
Evaluating is just basic fraction math:
For the summation, I'll try some coloring to see if that helps:
Notice that the 1's on top stay the same.
Notice that the 2 exponents on the bottom stay the same in all terms.
Notice that the red numbers go 1,2,3
Notice that the green numbers go 2,3,4, just 1 more than the red numbers.
So if k represents a red number, then the corresponding green number is k+1.
So each term is of the form
And k starts at 1 and goes to 3. We indicate that
with
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b) 3 + 6 + 9 + 12 + 15
The evaluation is simple addition, getting 45.
This one is easier than the first one.
They are the first 5 multiples of 3. They are
The
is the same on all the terms,
The numbers after the
go 1,2,3,4,5
So if k represents the numbers on the right of the
,
then k starts at 1 and goes up to and including 5:
So each term has the form
The summation is
Edwin