SOLUTION: A cyclist and a jogger start from a town at the same time and head for a destination 17 mi away. The rate of the cyclist is twice the rate of the jogger. The cyclist arrives 1.7 h

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Question 968016: A cyclist and a jogger start from a town at the same time and head for a destination 17 mi away. The rate of the cyclist is twice the rate of the jogger. The cyclist arrives 1.7 h before the jogger. Find the rate of the cyclist.
Answer by lwsshak3(11628) About Me  (Show Source):
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A cyclist and a jogger start from a town at the same time and head for a destination 17 mi away. The rate of the cyclist is twice the rate of the jogger. The cyclist arrives 1.7 h before the jogger. Find the rate of the cyclist.
let x=travel time of cyclist
x+1.7=travel time of jogger
rate=distance/travel time
..
17%2Fx=2%2A%2817%2F%28x%2B1.7%29%29 (rate of the cyclist is twice the rate of the jogger)
34x=17(x+1.7)
34x=17x+28.9
17x=28.9
x=1.7
17/x=17/1.7=10
rate of the cyclist=10 mph