SOLUTION: find three consecutive even integers such that four times the sum of the first and third integers is twenty less than six time the middle integer

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Question 96799: find three consecutive even integers such that four times the sum of the first and third integers is twenty less than six time the middle integer
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
x, x+2, x+4 are the three integers
4(x+x+4)=4 times the sum of the 1st and 3rd.
6(x+2)=6 times the middle.
Don't forget to add 20 to the left side to make it equal to the right!
4(2x+4)+20=6(x+2)
8x+16+20=6x+12
subtract 6x and 36 from both sides.
2x=-24
divide 2 into both sides. x=-12 x+2=-10 x+4=-8
Check:
4(-12+(-8))=4*-20=-80
6*-10=-60
-80 is 20 less than -60
Ed