SOLUTION: What is an equation of the line that passes through the point (-2,5) and is perpendicular to the line whose equation is y = 1/2x + 5? Please explain the steps to how you got the

Algebra ->  Linear-equations -> SOLUTION: What is an equation of the line that passes through the point (-2,5) and is perpendicular to the line whose equation is y = 1/2x + 5? Please explain the steps to how you got the       Log On


   

Question 967947: What is an equation of the line that passes through the point (-2,5) and is perpendicular to the line whose equation is y = 1/2x + 5?
Please explain the steps to how you got the answer. Thank you!
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The given equation is in the slope-intercept form
The form is:
+y+=+m%2Ax+%2B+b+ where
+m+ = slope
---------------------
+y+=+%281%2F2%29%2Ax+%2B+5+
Any line which is perpendicular to this line will
have slope =
+m%5B1%5D+=+-1%2Fm+
+m%5B1%5D+=+-1%2F%28%281%2F2%29%29+
+m%5B1%5D+=+-2+
----------------
Now I can use the general point-slope formula:
+%28+y+-+5+%29+%2F+%28+x+-%28-2%29+%29+=+-2+
+%28+y+-+5+%29+%2F+%28+x+%2B+2+%29+=+-2+
+y+-+5+=+-2%2A%28+x+%2B+2+%29+
+y+-+5+=+-2x+-+4+
+y+=+-2x+%2B+1+
--------------------
check:
slope = +-2+
OK
Does it go through ( -2, 5 ) ?
+y+=+-2x+%2B+1+
+5+=+-2%2A%28-2%29+%2B+1+
+5+=+4+%2B+1+
+5+=+5+
OK