SOLUTION: http://www.algebra.com/tutors/students/your-answer.mpl?question=967790
ur graph is on the x-axis. But my inequalities are x^2+2x+1>0. So for x^2+2x+1>0 can i say that x^2+2x+1 is
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-> SOLUTION: http://www.algebra.com/tutors/students/your-answer.mpl?question=967790
ur graph is on the x-axis. But my inequalities are x^2+2x+1>0. So for x^2+2x+1>0 can i say that x^2+2x+1 is
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Question 967792: http://www.algebra.com/tutors/students/your-answer.mpl?question=967790
ur graph is on the x-axis. But my inequalities are x^2+2x+1>0. So for x^2+2x+1>0 can i say that x^2+2x+1 is the y values of my graph? Please answer my question. Answer by josgarithmetic(39625) (Show Source):
You can put this solution on YOUR website! I agree essentially with Theo. The graph touches the horizontal axis for x=-1, and is everywhere else above the horizontal axis.
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