Question 967770: a man is five times as old as his son. Four years ago he was nine times as old. Find their present ages. Found 2 solutions by lwsshak3, josgarithmetic:Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! a man is five times as old as his son. Four years ago he was nine times as old. Find their present ages.
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let x=son's present age
5x=man's present age
..
4 yrs ago:
x-4=son's age
5x-4=man's age
5x-4=9(x-4)
5x-4=9x-36
4x=32
x=8
5x=40
son's present age=8
man's present age=40
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