SOLUTION: Find an equation for the parabola shown in the figure. http://www.webassign.net/waplots/a/6/5c377b7c207453d352fef3f6587777.gif (if a hyper link isn't attached then copy and p

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find an equation for the parabola shown in the figure. http://www.webassign.net/waplots/a/6/5c377b7c207453d352fef3f6587777.gif (if a hyper link isn't attached then copy and p      Log On


   



Question 967699: Find an equation for the parabola shown in the figure.
http://www.webassign.net/waplots/a/6/5c377b7c207453d352fef3f6587777.gif
(if a hyper link isn't attached then copy and paste to see the figure)I did add what the figure is showing below.
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Vertex:(-2,3)
with a point at (2,2)
So, what I knew about this question was that the basic equation for a parabola is (x-h)^2 = 4p(y-k)
which I substituted (-2,3) for (h,k)
(x+2)^2 = 4p(y-3)
But I'm stuck as to where the point(2,2) would go into that equation.

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
The point (2,2) is a point on the parabola.

%282%2B2%29%5E2=4p%282-3%29, which means you can solve for the factor, p.