SOLUTION: log(2x+21)-log5x=0,find the value of x.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: log(2x+21)-log5x=0,find the value of x.      Log On


   

Question 967677: log(2x+21)-log5x=0,find the value of x.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log(2x+21)-log5x=0,find the value of x.
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log[(2x+21)/(5x)] = 0
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(2x+21)/5x = 10^0
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2x+21 = 5x
3x = 21
x = 7
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Cheers,
Stan H.
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