SOLUTION: A rectangle is 5 cm longer than it is wide. If the length and breadth are increased by 2 cm each, the area increases by 50 cm^2. Find the dimension of the original rectangle.

Algebra ->  Average -> SOLUTION: A rectangle is 5 cm longer than it is wide. If the length and breadth are increased by 2 cm each, the area increases by 50 cm^2. Find the dimension of the original rectangle.      Log On


   

Question 967300: A rectangle is 5 cm longer than it is wide. If the length and breadth are increased by 2 cm each, the area increases by 50 cm^2. Find the dimension of the original rectangle.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Your description implies that width and breadth are the same direction.

x, length
y, breadth or width

x=y+5;

xy=A;
%28x%2B2%29%28y%2B2%29-xy=50
xy%2B2x%2B2y-4-xy=50
2x%2B2y-4=50
substitute now for x from the described relation with y.
2%28y%2B5%29%2B2y-4=50
...

Should be clear enough, no expected difficulty to finish.