SOLUTION: Given that log x = 3.7 and log y = 3, evaluate log (x^2 y^3)
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Question 967187
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Given that log x = 3.7 and log y = 3, evaluate
log (x^2 y^3)
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Theo(13342)
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log(x^2*y^3) is equal to log(x^2) + log(y^3) which is equal to 2 * log(x) + 3 * log(y) which is equal to 2 * 3.7 + 3 * 9 which is equal to 7.4 + 9 which is equal to 16.4.