SOLUTION: x=2^p y=2^q xy=32 2xy^2=32 Find the value of p and the value of q. Please give explanation.Thanks in advance!

Algebra ->  Expressions-with-variables -> SOLUTION: x=2^p y=2^q xy=32 2xy^2=32 Find the value of p and the value of q. Please give explanation.Thanks in advance!      Log On


   

Question 967038: x=2^p y=2^q xy=32 2xy^2=32 Find the value of p and the value of q. Please give explanation.Thanks in advance!
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
xy=2%5E%28p%2Bq%29=32
1.p%2Bq=5
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.
.
2xy%5E2=2%282%5Ep%29%282%5Eq%29%5E2=32
2%5E%28p%2B2q%29=16
2.p%2B2q=4
Subtract eq. 1 from eq. 2,
p%2B2q-p-q=4-5
q=-1
Then,
p=6