SOLUTION: Hello guys, I need help here: "The number of blues was two more than the total number of reds and greens. Three times the number of reds added to twice the number of greens was tw

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Hello guys, I need help here: "The number of blues was two more than the total number of reds and greens. Three times the number of reds added to twice the number of greens was tw      Log On

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Question 967004: Hello guys, I need help here:
"The number of blues was two more than the total number of reds and greens. Three times the number of reds added to twice the number of greens was twice the number of blues. If there were 22 total, how many were there of each color?"
Thank you in advance.

Found 2 solutions by Fombitz, MathTherapy:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1.B=2%28R%2BG%29
2.3R%2B2G=2B
3.B%2BG%2BR=22
Substituting from eq. 1 into eq. 2,
3R%2B2G=4%28R%2BG%29
3R%2B2G=4R%2B4G
R%2B2G=0
There's a problem here.
From this equation, one value is positive and the other is negative.
Can't have a negative number of reds, greens, or blues.
Please re-check the problem set up and repost.


Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!

Hello guys, I need help here:
"The number of blues was two more than the total number of reds and greens. Three times the number of reds added to twice the number of greens was twice the number of blues. If there were 22 total, how many were there of each color?"
Thank you in advance.
Number of reds:    highlight_green%284%29
Number of greens: highlight_green%286%29
Number of blues: highlight_green%2812%29