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Question 966879: Find two numbers to some is 0.71 and whose product is 0.1218
Find two numbers whose difference is .03 and who some is .79
Find two numbers who some is 1.33 and whose difference is .09 Thank you very much
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! A) Find two numbers to some is 0.71 and whose product is 0.1218
x + y = 0.71
xy = 0.1218
solve second equation for x
x = 0.1218 / y
substitute for x in first equation
(0.1218 / y) + y = 0.71
multiply both sides of = by y
0.1218 +y^2 = 0.71y
y^2 -0.71y + 0.1218 = 0
factor the polynomial
(y -0.42) * (y -0.29) = 0
there are two solution sets
x = 0.29, y = 0.42
x = 0.42, y = 0.29
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B) Find two numbers whose difference is .03 and who some is .79
x - y = 0.03
x + y = 0.79
solve frist equation for x
x = y +0.03
substitute for x in second equation
y +0.03 +y = 0.79
2y = 0.76
y = 0.38
x = 0.41, y = 0.38
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C) Find two numbers who some is 1.33 and whose difference is .09
x + y = 1.33
x - y = 0.09
solve second equation for x
x = y +0.09
substitute for x in first equation
y +0.09 +y = 1.33
2y = 1.24
y = 0.62
x = 0.71, y = 0.62
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