SOLUTION: Solve equation for x. x^2+4x+4=7 (Hint: Factor the left-hand side)? I believe the answer is 2+-sqrt7 Please help me. Thank you.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Solve equation for x. x^2+4x+4=7 (Hint: Factor the left-hand side)? I believe the answer is 2+-sqrt7 Please help me. Thank you.       Log On


   

Question 96673: Solve equation for x.
x^2+4x+4=7 (Hint: Factor the left-hand side)? I believe the answer is 2+-sqrt7
Please help me.
Thank you.

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Your answer is almost correct. You were given:
.
x%5E2+%2B4x+%2B+4+=+7
.
If you factor the left side you find that it is a perfect square and you get:
.
%28x%2B2%29%5E2+=+7
.
Now take the square root of both sides and you get:
.
x+%2B+2+=+sqrt%287%29
.
In which the square root is preceded by a +- sign. Subtract 2 from both sides to get:
.
x+=+-2+%2B-sqrt%287%29
.
You just missed the minus sign that precedes the 2.
.
Hope this helps you to understand the problem and the process for getting an answer.