SOLUTION: I'm having trouble with these! Help? For the following equation of a hyperbola, determine the center, vertices, foci and asymptotes, then sketch its graph: x^2-y^2-2x-4y-4=0 T

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I'm having trouble with these! Help? For the following equation of a hyperbola, determine the center, vertices, foci and asymptotes, then sketch its graph: x^2-y^2-2x-4y-4=0 T      Log On


   

Question 966729: I'm having trouble with these! Help?
For the following equation of a hyperbola, determine the center, vertices, foci and asymptotes, then sketch its graph:
x^2-y^2-2x-4y-4=0
Thank you!!
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square in x and y.
x%5E2-y%5E2-2x-4y-4=0+
%28x%5E2-2x%2B1%29-%28y%5E2%2B4y%2B4%29-4=1-4
%28x-1%29%5E2-%28y%2B2%29%5E2=1
Hyperbola
.
.
.
Center (1,-2)
Vertices (0%2C%7B%7B%7B-2) (2%2C%7B%7B%7B-2)
Asymptotes :
y=%281%2F1%29%28x-1%29-2 and y=-%281%2F1%29%28x-1%29-2
y=x-3 and y=-x-1