SOLUTION: During the first part of a canoe trip, David covered 60 kilometers at a certain speed. He then traveled 24 kilometers at a speed that was 4 kilometres per hour slower. If the total

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Question 966626: During the first part of a canoe trip, David covered 60 kilometers at a certain speed. He then traveled 24 kilometers at a speed that was 4 kilometres per hour slower. If the total time for the trip was 8 hours, what was the speed on each part of the trip?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
During the first part of a canoe trip, David covered 60 kilometers at a certain speed. He then traveled 24 kilometers at a speed that was 4 kilometres per hour slower. If the total time for the trip was 8 hours, what was the speed on each part of the trip?
***
let x=speed of first part of trip
x-4=speed of second part of trip
travel time=distance/speed
60%2Fx%2B24%2F%28x-4%29=8
lcd:x(x-4)
60(x-4)+24x=8x(x-4)
60x-240+24x=8x^2-32x
8x^2-116x+240=0
solve for x by quadratic formula:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a=8, b=-116, c=240
ans:
x=2.5 (reject)
or
x=12
..
x-4=8
speed of first part of trip=12 km/h
speed of second part of trip=8 km/h