SOLUTION: Given: Quad ABCD is a trapezoid Prove: A(Triangle ACD) = A(Triangle BCD) Statements: Reasons:

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Question 966259: Given: Quad ABCD is a trapezoid
Prove: A(Triangle ACD) = A(Triangle BCD)
Statements:

Reasons:

Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!

Let  ABCD  be a trapezoid with the bases  AB  and  DC,  and  AC  and  BD  be its diagonals.                      
(Figure 1).  We need to prove that the triangles  DELTAACD  and  DELTABCD  have equal areas.

Let us draw the altitudes  AE  and  BF  in the trapezoid  ABCD  from vertices  A  and  B 
to the base  DC  (Figure 1).
Notice that these altitudes are congruent as the opposite sides of the rectangular  ABFE.

Now,  the triangles  DELTAACD  and  DELTABCD  share the common base  DC  and have
congruent altitudes to the base.  Therefore,  these triangles have the same area.



                  Figure 1