SOLUTION: a contestant on a game show has a 1 in 6 chance of winning for each try. if the contestant has 2 tries, what is the probability that she does not win?

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Question 966236: a contestant on a game show has a 1 in 6 chance of winning for each try. if the contestant has 2 tries, what is the probability that she does not win?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
You're a little unclear about what you mean by win, once? twice?
In two tries, she can
WW
WL
LW
LL
Here's the probability for all the case,
WW
P=%281%2F6%29%281%2F6%29=1%2F36
WL
P=%281%2F6%29%285%2F6%29=5%2F36
LW
P=%285%2F6%29%281%2F6%29=5%2F36
LL
P=%285%2F6%29%285%2F6%29=25%2F36
So if winning means winning both tries,
P=1%2F36
If winning means winning at least one try,
P=%281%2B5%2B5%29%2F36=11%2F36